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x^2+42x-459=0
a = 1; b = 42; c = -459;
Δ = b2-4ac
Δ = 422-4·1·(-459)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-60}{2*1}=\frac{-102}{2} =-51 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+60}{2*1}=\frac{18}{2} =9 $
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